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Statement 1 : There can be maximum two p...

Statement 1 : There can be maximum two points on the line `p x+q y+r=0` , from which perpendicular tangents can be drawn to the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1` Statement 2 : Circle `x^2+y^2=a^2+b^2` and the given line can intersect at maximum two distinct points.

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Statement 1: There can be maximum two points on the line px+qy+r=0 ,from which perpendicular tangents can be drawn to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 Statement 2: Circle x^(2)+y^(2)=a^(2)+b^(2) and the given line can intersect at maximum two distinct points.

Number of points from which two perpendicular tangents can be drawn to both the ellipses E_1: x^2/(a^2+2)+y^2/b^2=1 and E_2:x^2/a^2+y^2/(b^2+1)=1 is

The points on the ellipse (x^(2))/(2)+(y^(2))/(10)=1 from which perpendicular tangents can be drawn to the hyperbola (x^(2))/(5)-(y^(2))/(1) =1 is/are

The points on the ellipse (x^(2))/(2)+(y^(2))/(10)=1 from which perpendicular tangents can be drawn to the hyperbola (x^(2))/(5)-(y^(2))/(1) =1 is/are

Statement 1 : If there is exactly one point on the line 3x+4y+5sqrt(5)=0 from which perpendicular tangents can be drawn to the ellipse (x^2)/(a^2)+y^2=1,(a >1), then the eccentricity of the ellipse is 1/3dot Statement 2 : For the condition given in statement 1, the given line must touch the circle x^2+y^2=a^2+1.

Statement 1: If there is exactly one point on the line 3x+4y+5sqrt(5)=0 from which perpendicular tangents can be drawn to the ellipse (x^(2))/(a^(2))+y^(2)=1,(a>1), then the eccentricity of the ellipse is (1)/(3). Statement 2: For the condition given in statement 1,the given line must touch the circle x^(2)+y^(2)=a^(2)+1

Statement 1 : If there is exactly one point on the line 3x+4y+5sqrt(5)=0 from which perpendicular tangents can be drawn to the ellipse (x^2)/(a^2)+y^2=1,(a >1), then the eccentricity of the ellipse is 1/3dot Statement 2 : For the condition given in statement 1, the given line must touch the circle x^2+y^2=a^2+1.

Find the points on the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))= 2 from which two perpendicular tangents can be drawn to the circle x^(2) + y^(2) = a^(2)