A metal rod of length l cuts across a uniform magnetic field B with a velocity v. If the resistance of the circuit of which the rod forms a part is r, then the force required to move the rod is

A metal rod of length l cuts across a unifrom magnetic field B with a velocity v. If the resistance of the circuit of which the rod forms a part is r, then the force required to move the rod is

A metallic rod completes its circuit as shown in the figure. The circuit is normal to a magnetic field of B=0.15 tesla. If the resistances of the rod is 3Omega the force required to move the rod with a constant velocity of 2m//sec is-

A conducting rod of length l is moving in a transverse magnetic field of strength B with veocity v. The resistance of the rod is R. The current in the rod is

A conducting rod of length l is moving in a transverse magnetic field of strength B with veocity v. The resistance of the rod is R. The current in the rod is

A glass rod of length l moves with velocity in a uniform magnetic field B. What is the e.m.f. induced in the rod ?

A glass rod of length l moves with velocity v in a uniform magnetic field B. What is the e.m.f induced in the rod?

A glass rod of length l moves with velocity v in a uniform magnetic field B. What is the e.m.f induced in the rod?

A metal rod of length l is placed normal to a uniform magnetic field B. The rod moves with velocity v perpendicular to the field. Show that motional emf across its ends is Blv.

A metallic rod of length L rotates at an angular speed omega, normal to a uniform magnetic field. If the resitance of rod is R the heat dissipated is: