In hydrogen atom, the transition takes place from `n = 3` to `n = 2`. If Rydberg's constant is `1.09 xx 10` per metre, the wavelength of the limit emitted is

In a hydrogen atom, the transition takes place from n = 3 to n = 2 . If Rydberg constant is 1.097xx10^(7)m^(-1) , the wavelength of the emitted radiation is

In a hydrogen atom, a transition takes place from n = 3 to n = 2 orbit. Calculate the wavelength of the emitted photon. Will the photon be visible ? To which spectral series will this photon belong? Given R =1.097 xx 10^(7) m^(-1)

In a hydrogen atom, a transition takes place from n = 3 to n = 2 orbit. Calculate the wavelength of the emitted photon. Will the photon be visible ? To which spectral series will this photon belong? Given R =1.097 xx 10^(7) m^(-1)

Energy level diagram of a hydrogen atom is shown below : (i)If a transition takes place from n=3 to n=2 orbit, calculate the wavelength of the radiation emitted. Identify the spectral series to which it belongs. (ii)Which transition results in emission of radiation of maximum wavelength ?

The wavelength of the radiation emitted by a hydrogen atom in the electronic transition from n=3 to n=2 is lambda . For the same transition in the singly ionized helium, the wavelength of the emitted radiation is

The electron in hydrogen atom jump from n_i = 3 orbit to n_f = 2 orbit. If R is the Rydberg constant then the wavelength lambda of the emitted radiation is

For hydrogen like atom, transition from n = 3 to n = 1 frequency is 192 x 10^15 then find frequency when transition takes place from n = 2 to n = 1