`(sintheta+sin3theta+.......n terms)/(costheta+cos3theta+.......n terms)` is equal to

(sintheta-2sin^3theta)/(2cos^3theta-costheta) = …………….

Prove that: (sintheta+sin3theta+sin5theta+… to n terms)/(costheta+cos3theta+cos5theta+…to n terms)= tan ntheta

Prove that: (sintheta+sin3theta+sin5theta+… to n terms)/(costheta+cos3theta+cos5theta+…to n terms)= tan ntheta

Prove that: (sintheta+sin3theta+sin5theta+… to n terms)/(costheta+cos3theta+cos5theta+…to n terms)= tan ntheta

(sin5theta+sin2theta-sintheta)/(cos5theta+2cos3theta+2cos^2theta+costheta) is equal to

If sin theta_1 + sin theta_2 + sintheta_3 =3 then cos theta_1 + cos theta_2 + costheta_3 is equal to

Prove that sin^(3)theta+sin^(3)3 theta+sin^(3)5 theta+....+n terms is equal to

Sum to terms of the series sintheta sin2theta + sin2thetasin3theta + sin3theta sin4theta +..... is equal to

if theta_1, theta_2, theta_3, ........, theta_n are in AP then (sintheta_1 + sintheta_2 + ....... + sintheta_n) / (costheta_1 + costheta_2 + costheta_3 + ...... + costheta_n ) =?

If sintheta+sin2theta+sin3theta=sinalpha and costheta+cos2theta+cos3theta=cosalpha , then theta is equal to