Railway lines are laid with gaps to allow for expansion. If the gap betweeen steel rails 60 m long be 3.60 cm at `10^(@)C`, then at what temperature will the lines just touch? Coefficient of linear expansion of steel `=11//10^(-6) .^(@)C^(-1)`.

The increase in dimensions of a body due to increase in temperature is called thermal expansion. Railway lines are laid with gaps to allow for expansion.If the gap between steel rails 60m long is 3.63 cm at 10°C ,then at what temperature will the line just touch?Coefficient of linear expansion for steel is 11×10^(-6) /oC

Railway lines are laid with gaps to allow for expansion. If the gap between the steel rails 66 m long be 3.63 cm at 10^(@) C . Then the temperature at which the lines touch (coefficient of linear expansion for steel = 11 xx 10^(-6)^(@) C^(-1) ) is

Railway tracks are laid with gaps for expansion. The gap between the steel rails 20 m long is 1.2 cm at 10^@C . The temperature at which the steel rails just touch each other is ( prop steel = 12 xx 10^-6//^@C)

Railway lines are laid with the gaps to allow for expansion. The gap between two lines is 0.5 cm at 10 °C. If the length of a line is 12 m then temperature at which the lines just touch each other is [alpha = 11 x 1O'6/ °C]

Gaps are left while laying the railway lines in order to allow for expansion. The gap between steel rails of length 65 m is 3.56 cm at 15^@C . Calculate the temperature at which the rails will just touch each other. Take, O_("steel") = 1.1 xx 10^(-5)@C^(-1)

A clock with a steel pendulum gives accurate time at 30^@C . Calculate the fractional loss or gain in time if temperature changes to 50^@C . Coefficient of linear expansion of steel = 12 xx 10^(-6) ""^@C^(-1)

Railway lines are laid with gaps to allow for expansion. If each line is 10 m long at 20^@C , what should be the length of the gap to be kept between two rails to allow for expansion if the maximum temperature that can be reached is 50^@C ? (alpha_(steel)=1.2 xx 10^-6//^@C)