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[" Q."5" If "P=[[(sqrt(3))/(2),(1)/(2)],[-(1)/(2),(sqrt(3))/(2)]],A=[[1,1],[0,1]]" and "Q=" PAPT then "],[" PT "Q^(2015)" P is : "],[" 1) "square[[0,2015],[0,0]]],[" 2) ",[[2015,1],[0,2015]]],[" 3) ",[[2015,0],[1,2015]]],[" 4) ",[[1,2015],[0,1]]]

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