If `a+b+c+d+e+1/[a+b+c+d+e]=2`, then find `(a+b+c+d+e)^5+1/(a+b+c+d+e)^5`

What will come next in the series ? a b a b c a b c d a b c d e a b c d e f a b c d ? 1) g 2) f 3) e 4) a 5) none of these

What should come next in the folowing letter series ? b a c b a c d b a c d e b a c d e f b a c d ? 1) c 2) d 3) e 4) f 5) g

The H.C.F. of a/b , c/d , e/f is equal to (a) (LCM of a , c , e)/(HCF of b , d , f) (b) (HCF of a , c , e)/(LCM of b , d , f) (c) (HCF of a , c , e)/(HCF of b , d , f) (d) (a c e)/(b df)

If a, b, c, d, e be 5 numbers such that a, b, c are in AP, b, c, d, are in GP & c, d, e are in HP then (i) Prove that a,c,e are in GP. (ii) Prove that e=(2b-a)^2//a . (iii) If a=2& e=18 , find all possible vlaues of b,c,d.

If real numbers a, b, c, d, e satisfy a+1=b + 2 = c+ 3 = d + 4 = e + 5 = a + b + c + d + e + 3 then find the value of a^2 + b^2 + c^2 + d^2 + e^2

If a/b=b/c=c/d=d/e=e/f=1/3, then find the value of ((a+b+c+d+e)/(b+c+d+e+f)) :

If a/b=b/c=c/d=d/e=e/f=1/3 , find the value of ((a+b+c+d+e)/(b+c+d+e+f)):

If a + c = b e and 1/b + 1/d = e/c , Prove that : a,b,c and d are in proportion.