An Indian bread ‘‘Roti’’ is a uniform disc of mass M and radius R. Before eating a person usually folds it about its diameter (say about x axis). After folding it a sector of angle `60^(@)` is removed from it. Find the moment of inertia of the remaining ‘‘Roti’’ about Z-axis

A uniform circular disc has a sector of angle 90^(@) removed from it. Mass of the remaining disc is M. Write the moment of inertia of the remaining disc about the axis x x shown in figure (Radius is R)

The moment of inertia of a disc, of mass M and radius R, about an axis which is a tangent and parallel to its diameter is

The moment of inertia of a ring of mass M and radius R about PQ axis will be

The moment of inertia of a ring of mass M and radius R about PQ axis will be

The moment of inertia of a ring of mass M and radius R about PQ axis will be :-

If the radius of gyration of a solid disc of mass 10 kg about an axis is 0.40 m, then the moment of inertia of the disc about that axis is

A solid sphere of mass M and radius R is divided into two unequal parts. The first parts has a mass of (7M)/8 and is converted into a uniform disc of radius 2R. The second part is converted into a uniform solid sphere. Let I_(1) be the moment of inertia of the uniform disc about its axis and I_(2) be the moment of inertia of the sphere made from remaining part about its axis. The ratio I_(1)//I_(2) is 140/x . Find the value of x.