A body of mass 5 kg statrs from the origin with an initial velocity `vec(u) = (30 hat(i) + 40 hat(j)) ms^(-1)`. If a constant force `(-6 hat(i) - 5 hat(j))N` acts on the body, the time in which they component of the velocity becomes zero is

A particle has initial velocity vec(v)=3hat(i)+4hat(j) and a constant force vec(F)=4hat(i)-3hat(j) acts on the particle. The path of the particle is :

A body of mass 5 kg starts from the origin with an intial with an intial velocity vec (u) = 30hat(i) + 40hat(j). . If the body collides with a wall and after collision its velocity becomes vec(v) = - 30 hat (i) + 40 hat (j) , then what is change in momentum of body ?

A body of mass 5 kg starts from the origin with an intial with an intial velocity vec (u) = 30hat(i) + 40hat(j). . If the body collides with a wall and after collision its velocity becomes vec(v) = - 30 hat (i) + 40 hat (j) , then what is change in momentum of body ?

A particle of mass 2kg moves with an initial velocity of (4hat(i)+2hat(j))ms^(-1) on the x-y plane. A force vec(F)=(2hat(i)-8hat(j))N acts on the particle. The initial position of the particle is (2m,3m). Then for y=3m ,

A body with mass 5 kg is acted upon by a force vec(F) = (- 3 hat (i) + 4 hat (j)) N . If its initial velocity at t =0 is vec(v) = (6 hat(i) - 12 hat (j)) ms^(-1) , the time at which it will just have a velocity along the y-axis is :

A force (3 hat(i)+4 hat(j)) acts on a body and displaces it by (3 hat(i)+4 hat(j))m . The work done by the force is

What is the value of linear velocity, if vec(omega) = 3hat(i)-4 hat(j) + hat(k) and vec(r) = 5hat(i)-6hat(j)+6hat(k)

A particle starts from the origin with velocity vec u= (2hat i - 4 hat j) m/s with constant acceleration (3 hat I + 5 hat j) m/s^2 . After travelling for 2 seconds, its distance from the origin is

A body is projected from the ground with a velocity vec(v)= (3 hat(i) + 10 hat(j)) ms^(-1) . The maximum height attained and the range of the body respectively are (given g= 10 ms^(-2) )

A body with mass 5 kg is acted upon by a force vec(F) = (- 3 hat (i) + 4 hat (j)) N . If its initial velocity at t =0 is vec(v) = 6 hat(i) - 12 hat (j) ms^(-1) , the time at which it will just have a velocity along the y-axis is :