Two metal sphere of capacitance `C_(1) andC_(2)` carry some charges. They are put in contact and then separated. If final charges `Q_(1) and Q_(2)` on them, then:

Two metal spheres of capacitances C_1 and C_2 carry some charges . They are put in contact and then seperated.The final charges Q_1 and Q_2 on them will satisfy

Two metal spheres of capacitances C_1 and C_2 carry some charges . They are put in contact and then seperated.The final charges Q_1 and Q_2 on them will satisfy

Two metal spheres of capacitances C_1 and C_2 carry some charges . They are put in contant and then seperated.The final charges Q_1 and Q_2 on them will satisfy

Two identical conducting spheres M and N has charge q_M and q_N respectively. A third identical neutral spehre P is brought in contact with M and then separated. Now, sphere P is brought in contact with N and then separated. Find out final charge on the spehre P.

Two capacitors of capacitances C_(_1) and C_(2) are connected in parallel across a battery. If Q_(1) and Q_(2) respectively be the charges on the capacitors, then (Q_(1))/(Q^(2)) will be equal to

Two charged bodies of charges +q, -3q are brought in contact and separated. The charges prossed by each body after separation.

Charges q_(1) , q_(2) and q_(3) are placed on capacitors of capacitance C_(1) , C_(2) and C_(3) , respectively, arranged in series as shown. Switch S is there closed. What are the final charges q'_(1) , q'_(2) and q'_(3) on the capacitors? Given q_(1)=30muC , q_(2)=muC , q_(3)=10muC , C_(1)=10muF , C_(2)=20muF , C_(3)=30muF and epsilon=12"volt"

Charges q_(1) , q_(2) and q_(3) are placed on capacitors of capacitance C_(1) , C_(2) and C_(3) , respectively, arranged in series as shown. Switch S is there closed. What are the final charges q'_(1) , q'_(2) and q'_(3) on the capacitors? Given q_(1)=30muC , q_(2)=muC , q_(3)=10muC , C_(1)=10muF , C_(2)=20muF , C_(3)=30muF and epsilon=12"volt"

wo capacitors of capacitances C_(1) and C_(2) are connected in parallel across a battery. If Q_(1) and Q_(2) respectively be the charges on the capacitors, then (Q_(1))/(Q^(2)) will be equal to