y=e^(x)(A cos x+B sin x)

Obtain the differential equation by eliminating arbitrary constants. y=e^(2x)(A cos x+B sin x)

The differential equation of the family of curves y=e^(2x)(a cos x+b sin x) where, a and b are arbitrary constants, is given by

The differential equation of the family of curves y=e^(2x)(a cos x+b sin x) where, a and b are arbitrary constants, is given by

Form the differential equation from the following y = e^(x)(A cos 2x + B sin 2x)

If y = e^(2x)(A cos 3x - B sin 3x) , then y satisfies

Form the differential equation for y=e^(2x)[A cos 3x-B sin 3x]

Find the differential equation for the following y = e^(3x) (A cos 2x+B sin 2x)

Find the differential equation from y = e^x (A cos 2x + B sin 2x) , where A and B are arbitrary constants.