The K.E. of electron and photon is same then relation between their De-Broglie wavelength :

A proton and an electron initially at rest are accelerated by the same potential difference. Assuming that a proton is 2000 times heavier than an' electron, what will be the relation between the de Broglie wavelength of the proton (lambda_(p)) and that of electron (lambda_(e)) ?

A proton and an electron initially at rest are accelerated by the same potential difference. Assuming that a proton is 2000 times heavier than an electron, what will be the relation between the de Broglie wavelength of the proton (lambda_p) and that of electron (lambda_e)

According to de-Broglie hypothesis, the wavelength associated with moving electron of mass 'm' is 'lambda_(e)' . Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is 'lambda_(p)' . If the energy (E) of electron and photonm is same, then relation between lambda_e and 'lambda_(p)' is

If an electron and a proton have the same KE , the ratio of the de Broglie wavelengths of proton and electron would approximately be

An electron of mass m and a photon have same energy E . The ratio of de - Broglie wavelengths associated with them is :

An electron of mass m and photon have same energy E. The ratio of de-Broglie wavelength associated with them is:

An electron of mass m and a photon have same energy E. The ratio of de Broglie wavelength associated with them is

An electron of mass m and a photon have same energy E . The ratio of de - Broglie wavelengths associated with them is :

If a proton and electron have the same de-Broglie wavelength, then

If a proton and electron have the same de Broglie wavelength, then