Show that `f: [-1, 1] ->R`, given by `f(x) = (x)/(x+2)` is one- one . Find the inverse of the function `f: [-1, 1]→ "Range" f.`

Explanation

To show that the function \( f: [-1, 1] \to \mathbb{R} \) defined by \( f(x) = \frac{x}{x+2} \) is one-to-one and to find its inverse, we can follow these steps:

### Step 1: Prove that \( f \) is one-to-one

To prove that \( f \) is one-to-one, we need to show that if \( f(x_1) = f(x_2) \), then \( x_1 = x_2 \).

Assume \( f(x_1) = f(x_2) \):
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