[" 5.The distance of a point on the ellipse "x^(2)+3y^(2)=6" from its centre is equal to "2" .Find the eccentric "],[" angles."]

The distance of a point on the ellipse x^(2) + 3y^(2) = 6 from its centre is 2. Find the eccentric angle of the point.

The distance of a point of the ellipse x^(2) + 3y^(2) = 6 from its centri is 2 , find the eccentric angle of the point .

If the distrance of a point on the ellipse 4x^(2) +9y^(2) =36 from its centre is 2, then the eccentric angle of the point is-

The distance of a point on the ellipse x^2/6 + y^2/2 = 1 from the centre is 2. Find the eccentric angle of the point.

The distance of a point on the ellipse x^(2)//6+y^(2)//2=1 from the centre is 2. The eccentric angle of the point is

The distance of a point on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 from the centre is 2 Then the eccentric angle of the point is

The distance of a point on the ellipse (x^2)/6+(y^2)/2=1 from the center is 2. Then the eccentric angle of the point is

If the distance of a point on the ellipse (x^(2))/(6) + (y^(2))/(2) = 1 from the centre is 2, then the eccentric angle of the point, is

The distance of a point on ellipse (x^(2))/(6) + (y^(2))/(2) = 1 from its centre is sqrt(2) . The eccentric is sqrt(2) angle of the point will be

The distance of point on the ellipse x^2 + 3y^2 = 6 from the centre is 2. Find the eccentric angle of the point in the first quadrant. Also find the equation of the tangent at the point.