If A is skew-symmetric and `B=(I-A)^(-1)(I+A)`, then B is

If A is a skew symmetric matrix, then B=(I-A)(I+A)^(-1) is (where I is an identity matrix of same order as of A )

If A is a skew symmetric matrix, then B=(I-A)(I+A)^(-1) is (where I is an identity matrix of same order as of A )

If A is a skew symmetric matrix, then B=(I-A)(I+A)^(-1) is (where I is an identity matrix of same order as of A )

If A is a skew symmetric matrix, then B=(I-A)(I+A)^(-1) is (where I is an identity matrix of same order as of A )

Let A be a skew-symmetric matrix, B= (I-A) (I+A)^(-1) and X and Y be column vectors conformable for multiplication with B. Statement-1 (BX)^(T) (BY) = X^(T) Y Statement- 2 If A is skew-symmetric, then (I+A) is non-singular.

If A is skew symmetric matrix, then I - A is (where I is identity matrix of the order equal to that of A)

If A is skew symmetric matrix, then I - A is (where I is identity matrix of the order equal to that of A)

A is a real skew symmetric such that A^(2)+I=0 then

If A=[a_(i j)] is a square matrix of even order such that a_(i j)=i^2-j^2 , then (a) A is a skew-symmetric matrix and |A|=0 (b) A is symmetric matrix and |A| is a square (c) A is symmetric matrix and |A|=0 (d) none of these

If A is a symmetric and B skew symmetric matrix and (A+B) is non-singular and C=(A+B)^(-1)(A-B), then prove that