The maximum velocity of a particle executing SHM is `100cms^(-1)` and the maximum acceleration is `157cms^(-2)` determine the periodic time

The maximum velocity of a particle executing SHM is v_(m)=picm*s^(-1) and the maximum acceleration is a_(m)=pi^(2)cm*s^(-2) . Determine the time period and the amplitude of motion of the particle.

The maximum displacement of a particle executing SHM is 1 cm and the maximum acceleration is (1.57)^(2)cm//s^(2) . Its time period is……………..

The maximum displacement of a particle executing S.H.M. is 1 cm and the maximum acceleration is (1.57)^(2) cm per sec^(2) . Then the time period is

The maximum speed of a particle executing SHM is 10 m/s and maximum acceleration is 31.4m//s^(2) . Its periodic time is

The maximum speed of a particle executing S.H.M. is 1 m/s and its maximum acceleration is 1.57 m// sec^(2) . The time period of the particle will be

A particle executing SHM has a maximum speed of 30 cm s^(-1) and a maximum acceleration of 60 cm s^(-1) . The period of oscillation is

A particle executing SHM has a maximum speed of 30 cm s^(-1) and a maximum acceleration of 60 cm s^(-1) . The period of oscillation is