30+1h+5c^(2)

(1+x)^(10)*(1+(1)/(x))^(20)is1^(30)C_(5)(2)^(10)C_(5)-3)^(20)C_(5)-4)^(30)

For the equilibrium : I: C_(6)H_(5)COOH+H_(2)OhArr C_(6)H_(5)COO^(-)+H_(3)O^(+),K_(1)=6.30xx10^(-5) II: C_(6)H_(5)COOH+OH^(-)hArrC_(6)H_(5)COO^(-)+H_(2)O, K_(2)=6.30xx10^(9) III: H_(2)O+H_(2)OhArr H_(3)O^(+)+OH^(-), K_(3)=? K_(3) using above equilibria is :

(1)/(1.23)+(1)/(2.3.4)+(1)/(3.4.5)+(1)/(4.5.6)= a) (7)/(30) b) (11)/(30) c) (13)/(30) d (17)/(30)

At 30°C 0.1M acetic acid ionizes to the extent of 1%. The P^H of 0.1M acetic acid at 30°C is (a) 1 (b) 3 (c) 4 (d) 2

If the value of the sum 29(.^(30)C_(0))+28(.^(30)C_(1))+27(.^(30)C_(2))+…….+1(.^(30)C_(28))-(.^(30)C_(30)) is equal to K.2^(32) , then the value of K is equal to

Why does not (C) gives (D) or (D_(1)) on treatment with alcoholic KOH or with C_(2)H_(5)ONa+C_(2)H_(5)OH ?

Why does not (C) gives (D) or (D_(1)) on treatment with alcoholic KOH or with C_(2)H_(5)Ona+C_(2)H_(5)OH ?

^5C_(1)+^(5)C_(2)+^(5)C_(3)+^(5)C_(4)+^(5)C_(5) is equal to 30 b.31c.32d.33

In C^(1) H_(3) C^(2) -= C^(3) - C^(4) H_(2) - C^(5)H = C^(6) H_(2) , hybridisation state of carbon number 1 , 3 and 5 are respectively -

Show that ""^(30)C_(0) +""^(30)C_(1)+""^(30)C_(2) +…+ ""^(30)C_(14) =2^(29)-(1)/(2) (""^(30)C_(15))