(cot^(2)theta(sec theta-1))/((1+sin theta))=sec^(2)theta*((1-sin theta)/(1+sec theta))

Prove the following identity : cot^2 theta ((sec theta-1)/(1+sin theta))+ sec^2 theta ((sin theta-1)/(1+sec theta)) =0 .

What will be the value of following identities : (cot^(2) theta (sec theta -1))/((1+ sin theta))+ (sec^(2)theta (sintheta -1))/((1+ sec theta))

cot^(2) theta ((sec theta -1)/(1+ sin theta ))+ sec^(2) theta ((sin theta -1)/( 1+ sec theta )) =

The trigonometric expression: cot^(2)[(sec theta-1)/(1+sin theta)]+sec^(2)theta[(sin theta-1)/(1+sec theta)] has the value has the

Prove: (1+sec theta)/(sec theta)=(sin^(2)theta)/(1-cos theta)

Prove :(cos theta)/(1+sin theta)+(cos theta)/(1-sin theta)=2sec theta

(tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)

(tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)

(tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)