The `pK_(a1)` and `pK_(a2)` of an amino acid are 2.3 and 9.7 respectively. The isoelectric point of the amino acid is:

Options

A. 6
B. 3.7
C. 12
D. 7.4

Explanation

To find the isoelectric point (pI) of the amino acid, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Isoelectric Point (pI)**:
The isoelectric point is the pH at which the amino acid has no net charge. This occurs when the positive and negative charges balance each other out.

2. **Identify the Given Values**:
We are given:
- \( pK_{a1} = 2.3 \)
- \( pK_{a2} = 9.7 \)

3. **Use the Formula for Isoelectric Point**:
The formula to calculate the isoelectric point (pI) is:
\[ pI = \frac{pK_{a1} + pK_{a2}}{2} \]

4. **Plug in the Values**:
Substitute the given values into the formula:
\[ pI = \frac{2.3 + 9.7}{2} \]

5. **Calculate the Sum**:
First, calculate the sum of \( pK_{a1} \) and \( pK_{a2} \):
\[ 2.3 + 9.7 = 12.0 \]

6. **Divide by 2**:
Now, divide the sum by 2 to find the isoelectric point:
\[ pI = \frac{12.0}{2} = 6.0 \]

7. **Conclusion**:
Therefore, the isoelectric point of the amino acid is:
\[ \text{pI} = 6.0 \]

### Final Answer:
The isoelectric point of the amino acid is **6.0**.