An optically pure compound `A,` gave an `[alpha]_(D)^(25)=+30^(@),` while a mixture of `A` and its enantiomer `B`, gave `[alpha]_(D)^(25)=+15^(@),` . The ratio of `A` to `B` in the mixture is

Options

A. 1 to 3
B. 3 to 1
C. 1 to 2
D. 2 to 1

Answer

B

Explanation

`(15)/(30)xx100=50`
Thus the mixture is 50% opticaaly pure. Hence the amount of
`A=50+25=75 B=0+25=25`