[" the "(x-y+1)(cy)/(cz)=x-y+2],[" Where "(x-y=x)]

(x-y+1)(dy)/(dx)=x-y+2 , where x-y=u

if x+y+z=0,then Prove that (xyz)/((x+y)(y+z)(z+x))=-1 where(x!=-y,y!=-z,z!=-x)

Solve: 5/(x+y)-2/(x-y)=-1,\ \ \ (15)/(x+y)+7/(x-y)=10 , where x+y!=0 and x-y!=0.

If x^(y)=y^(x) then ((x)/(y))^((x)/(y))=x^((x)/(y)-k) where k=

If (dy)/(dx)=(x-y+2)/(x-y+1), where u=x-y , then

If (x-1)^2+(y-2)^2 = (x-1)(y-2) , where x and y are integers, then the value of 2x + 3y is

If (x)/(y)+(y)/(x)=-1 , where x,y ne 0 then the value of (x^3-y^3) is

( Solve: )/(x+y)-(2)/(x-y)=-1,quad (15)/(x+y)+(7)/(x-y)=10 where x+y!=0 and x-y!=0

The greatest value of c in R for which the x-cy-cz=0 system of linear equations cx-y+cz,=0 has a non-trival solution,is:

Show that the general solution of the differential equation (dy)/(dx)+(y^2+y+1)/(x^2+x+1)=0 is given by ((x+y)+1)=A(1-x-y-2 x y) , where A is parameter.