Let `R = {(x, y): x^2+y^2=1, x, y in R}` be a relation in `R`. Then the relation `R` is

Let A={1,2,3,...10} and R={(x, y) : x+2y=10, x, y in A} be a relation A. Then, R^(-1) =

If R={(x,y):x^(2)+y^(2)<=4;x,y in Z} is a relation on Z, write the domain of R.

If R ={ (x,y) : x,y in z, x^(2) +y^(2) le 4 } is a relation on Z then domain of R is

Let A={1,2,3,...10} and R={(x,y):x+2y=10,x,y in A} be a relation A.Then,R^(-1)=

Let R= {x,y):x+2y=8} be a relation on N . write the range of R .

Let 'R' be the relation defined on the of natural numbers 'N' as , R={(x,y):x+y=6} ,where x, y in N then range of the relation R is

Let a relation R in the set of natural number be defined by (x,y) in R iff x^(2)-4xy+3y^(2)=0 for all x,y in N . Then the relation R is :

Let R be a relation on the set of natural numbers ,defined as R ={(x,y):x+2y=20, x,y varepsilon N} and x varepsilon {1,2,3,4,5} .Then ,the range of R is :

For real numbers x and y define x\ R\ y if x - y + sqrt(2) is an irrational number. Then the relation R is