The value of `^^_(m)^(infty)` for KCl and `KNO_(3)` are `149.86` and `154.96 Omega^(-1) cm^(2) mol^(-1)`
Also `lambda_(Cl^(-))^(infty)` is `71.44 " ohm"^(-1) cm^(2)mol^(-1)` The value of `lambda_(NO_(3)^(-))^(infty)` is

The values of ^^_(m)^(oo) for KCl and KNO_(3) are 149.86 and 154.96Omega^(-1)cm^(2)"mol"^(-1) . Also lambda_(Cl)^(oo) is 71.44 ohm^(-1)cm^(2) "mol"^(-1) . The value of lambda_(NO_(3)^(-))^(oo) is

The values of ^^_(m)^(oo) for KCl and KNO_(3) are 149.86 and 154.96Omega^(-1)cm^(2)"mol"^(-1) . Also lambda_(Cl)^(oo) is 71.44 ohm^(-1)cm^(2) "mol"^(-1) . The value of lambda_(NO_(3)^(-))^(oo) is

The lamda^(@) values of KCl and KNO_(3) are 149.9 and 144.9 S cm^(2)mol^(-1) respectively. Also lamda^(@) for Cl^(-) is 71.44 S cm^(2)mol^(-1) .The lamda^(@) value of NO_(3)^(-) ion.

The values of Lambda_(m)^(@) for the aqueous solution of KCl and KNO_(3) are 149.86ohm^(-1)"cm"^(2)mol^(-1) and 145 ohm^(-1)cm^(2)mol^(-1) , respectively. If lambda_(m)^(@)(Cl^(-)) is "76.44 ohm"^(-1)."cm"^(2)."mol"^(-1) then lambda_(m)^(@)(NO_3^(-)) will be?

The value of Lambda_(eq)^(oo) for NH_(4)Cl, NaOH and NaCl are 149.74, 248.1 and 126.4 Omega^(-1) cm^(2)" equiv"^(-1) . The value of Lambda_(eq)^(oo) of NH_(4)OH is

The values of Lambda_(eq)^(@) of KI and KCl solutions are 150.30 and "149.90 ohm"^(-1)."cm"^(2)."g-equiv"^(-1) respectively. If lambda^(@) value of Cl^(-) ion is "76.34 ohm"^(-1)."cm"^(2)."g - equiv"^(-1) , find the value of lambda_(I^(-))^(@) .

If the values of wedge_(infty) of NH_(4)Cl, NaOH and NaCl are 130, 217 and 109 ohm^(-1) cm^(2) equiv^(-1) respectively, the wedge_(infty) of NH_(4)OH in ohm^(-1) cm^(2) equiv^(-1) is