A `100 Omega` resistance is connected in series with a `4 H` inductor. The voltage across the resistor is, `V_(R ) = (2.0 V) sin (10^(3) t)`.
Find amplitude of the voltage across the inductor.

A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is, V_(R ) = (2.0 V) sin (10^(3) t) . Find the inductive reactance

A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is, V_(R ) = (2.0 V) sin (10^(3) t) . Find the expression of circuit current

A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is V_(R) = 2 sin (1000 t) V . The voltage across the inductors is

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expession of circuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expession of circuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expessinocircuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

The current through an inductor of 1H is given by i =3t sin t . Find the voltage across the inductor.

A coil of negligible resistance is connected in series with 90 Omega resistor across a 120 V - 60 Hz line. A voltmeter reads 36 V across the resistance. Find the voltage across the coil and Inductance of the coil