[f(x)=2x^(2)+3x+5" satisfies LMVT at "x=2" on the clo "],[[" (B) "4," EXERCISE "(C)6]]

If the function f(x)=2x^(2)+3x+5 satisfies LMVT at x=2 on the closed interval [1,a] then the value of 'a' is equal to

If y = (3x+5)e^(-2x) , then y satisfies

If f (x) = -2x + 5 , what is f ( -3x ) equal to ?

If f(x-2)=2x^2+3x-5 , find f(x) and prove that f(-1) = 0.

If the function f(x)=logx, x in [1, e] , satisfies all the conditions of LMVT, then the value of c is

For f(x)={[x^(3),,x =1] , LMVT holds on [0,2] . The value of b and the value of c in (0,2) is

Statement 1: For the function f(x)=x^(2)+3x+2,LMVT is applicable in [1,2] and the value of c is 3/2. Statement 2: If LMVT is known to be applicable for any quadratic polynomial in [a,b], then c of LMVT is (a+b)/(2) .

If f(x) = x^2 - 3x + 4 , then find the values of x satisfying the equation f(x) = f(2x + 1) .

(i) If f(x) = 3x^(4)- 5x^(2) + 7, " find " f(x-1) (ii) If f(x) = x^(2) - 3x + 4 , then find the values of x satisfying f(x) = f(2x+1)