[[(11)/(15+)+(sqrt(3))/(22),(bar(20))/(25),(5)/(10)],[3+sqrt(55),(25)/(15),(10)/(25)]|=

Given x, y in R , x^(2) + y^(2) gt 0 . Then the range of (x^(2) + y^(2))/(x^(2) + xy + 4y^(2)) is (a) ((10 - 4 sqrt(5))/(3),(10 + 4 sqrt(5))/(3)) (b) ((10 - 4 sqrt(5))/(15),(10 + 4 sqrt(5))/(15)) (c) ((5- 4 sqrt(5))/(15),(5 + 4 sqrt(5))/(15)) (d) ((20- 4 sqrt(5))/(15),(20 + 4 sqrt(5))/(15))

sqrt(11)+sqrt(3),sqrt(20),sqrt(5)sqrt(15)+sqrt(22),sqrt(25),sqrt(10)3+sqrt(55),sqrt(15),sqrt(25)]|=

|{:(sqrt(14)+sqrt3,sqrt(20),sqrt5),(sqrt(15)+sqrt(28),sqrt(25),sqrt(10)),(3+sqrt(70),sqrt(15),sqrt(25)):}|=.......

The value of 1/(sqrt(3.25) + sqrt(2.25)) + 1/(sqrt(4.25) + sqrt(3.25))+ 1/(sqrt(5.25) + sqrt(4.25)) + 1/(sqrt(6.25) + sqrt(5.25)) is:

f(x)=sqrt(25-x^(2)) in [1,5]

sqrt(110(1)/(4))=?(a)10.25(b)10.5(c)11.5 (d) 19.5

Solve: (sqrt((25)/9)-sqrt((64)/(81)))-:sqrt((16)/(324))=? (a) 4.5 (b) 2.5 (c) 1.5 (d) 3.5

Solve by factorization: 3sqrt(5)x^(2)+25x-10sqrt(5)=0

The value of (10 sqrt(6.25))/(sqrt(6.25) - 0.5) is: