In `DeltaA B C , a=2b and |A-B|=pi/3` then `/_C` is

In a DeltaABC , a=2b and |A-B|=(pi)/(3) . Then /_C is

In DeltaABC, a=2b,|A-B|=(pi)/(3) then angle C =

If in a !ABC , a =2b ,and abs(A-B)=(pi)/3 then C =

In a DeltaA B C ,\ ifb=20 ,\ c=21\ a n dsinA=3/5 find adot

In a DeltaA B C , if b=sqrt(3), c=1 a n d /_A=30^0, then find a

In a A B C , prove the following : In a DeltaA B C ,\ if\ a=5, \ b=6\ a n d\ C=60^0, show that its area is (15sqrt(3))/2 sq.units dot

In DeltaA B C , it is known that /_B=/_Cdot Imagine you have another copy of DeltaA B C Is DeltaA B C~=DeltaA C B State the three pairs of matching parts you have used to answer (i). Is it true to say that A B=A C ?

In a DeltaA B C , prove the following : a\ cos A+b\ cos B+c cos C=2bsinA sin\ Cdot

In DeltaA B C , right-angled at B, A B\ =\ 24\ c m ,\ B C\ =\ 7\ c m . Determine: (i) sin A, cos A (ii) sin C, cos C

In a DeltaA B C prove that cos ((A+B)/2)=sin (C/2).