14 g of `O_2` and 4 g of `C_3H_8` are allowed to react to the maximum possible extent to form only CO and `H_2O`. Find the weight of CO formed.

14 g of O_2 and 4 g of C_3H_8 are allowed to react the maximum possible extent to form only CO and H_2O . Find the weight of CO formed.

4g C_3H_8 and 14 g O_2 are allowed to react to the maximum possible extent to form only CO and H_2O Find the weight of CO formed.

27 g C and 48 g O_2 are allowed to react completely to form CO and CO_2 .The weight ratio of CO and CO_2 formed, is :

2g of H_(2) and 1g O_(2) are allowed to react according to following equation 2H_(2)(g)+O_(2)(g) to 2H_(2)O(g) Amount of H_(2)O formed in the reaction will be:

1.5 g of H_2 react with 14.5 g of O_2 to form water Calculate the amount of water that is formed in the reaction.

1.5 g of H_2 react with 14.5 g of O_2 to form water Which is the limiting reagent?

Dihydrogen gas used in Haber's process is produced by reacting methane form natural gas with high temperature steam..The first stange reaction involves the formation of CO and H_2 .In second stage , CO formed in first stage,CO formed in first stage is reacted with more steam ion water gas shift reaction, CO(g)+ h_2o(g) hArr CO_2(g) +H_2(g) If a reaction vessel at 400^@C is charged with a n equimolar mixture of CO and steam such that P_(co) =P_(H_2O) = 4.0 bar what will be the partial pressure of H_2 at equilibrium? k_p =0.1

3g of hydrogen reacts with 30g of oxygen to yield H_2O . Calculate the maximum amount of H_2O that can be formed.

1.5 g of H_2 react with 14.5 g of O_2 to form water Calculate the amount of the reactant which remains unreacted

3.00 g of H_(2) react with 28.00 g of O_(2) to yield H_(2)O . Calculate the maximum amount of H_(2)O that can be formed.