An ac source of voltage `V=V_(m)sin omega t` is connected across the resistance R as shown in figure. The phase relation between current and voltage for this circuit is

An ac source of voltage V = V_ 0sin omegat is connected to a series combination of L, C and R. Use the phasor diagram to obtain expressions for impedance of the circuit and phase with the voltage. What is circuit in this condition called?

An AC voltage source V=V_0sinomegat is connected across resistance R and capacitance C as shown in figure. It is given that omegaC=1/R . The peak current is I_0 . If the angular frequency of the voltage source is changed to omega/sqrt3, then the new peak current in the circuit is .

An AC voltage source V=V_0siomegat is connected across resistance R and capacitance C as shown in figureure. It is given that R=1/omegaC . The peak current is I_0 . If the angular frequency of the voltage source is changed to omega/sqrt3, then the new peak current in the circuit is .

An AC voltage source V=V_0siomegat is connected across resistance R and capacitance C as shown in figureure. It is given that R=1/omegaC . The peak current is I_0 . If the angular frequency of the voltage source is changed to omega/sqrt3, then the new peak current in the circuit is .

A 50 Hz a.c. source of 20 V is connected across R and C as shown in figure. The voltage across R is 12 V. The voltage across C is