In `Delta ABC,a/cos A= b/cos B =c/cos c` ; If `b=2` 'then the area of the triangle is

In Delta ABC,a(b cos C-c cos B)=

In Delta ABC, cos A + cos (B-C)=

In Delta ABC , a( b cos C - c cos B) =

In a Delta ABC , cos (A + B) + cos C =

In Delta ABC, (b-a cos C)/(c-a cos B)=

In a triangle ABC, if (cos A)/(a) =(cos B)/(b ) =(cos C)/(c) and the side a=2, then the area of the triangle is-

In a triangle ABC, a cos A+b cos B+ c cos C=