IF the function `f(x) =sqrt(x^2+kx+1)/(x^2-k)` is continuous for every `x epsilon R ` then 1)`kepsilon [-2,0)` 2)`kepsilon (0,oo)` 3)`kepsilon (-oo,0)` 4)`kepsilon R`

If the function f(x)=(sqrt(x^(2)+kx+1))/(x^(2)-k) is continuous for every x in R , then possible integral values of k

If the function f(x)=((e^(kx)-1)tankx)/(4x^(2)),x ne 0 =16" "x=0 is continuous at x=0, then k= . . .

f (x) = ((e^(kx)-1)(sin kx))/(4x^(2)) , x ne 0, f(0) = 9 , is continuous at x = 0 , then k =

The function f(x)=log x-(2x)/(x+2) is increasing for all A) x in(-oo,0) , B) x in(-oo,1) C) x in(-1,oo) D) x in(0,oo)

The domain of the function f(x)=sqrt(x^2-[x]^2) , where [x] is the greatest integer less than or equal to x , is (a) R (b) [0,+oo) (c) (-oo,0) (d) none of these

Let f(x)=[x]cos ((pi)/([x+2])) where [ ] denotes the greatest integer function. Then, the domain of f is (a) x epsilon R, x not an integer (b) x epsilon (-oo, -2)uu[-1,oo) (c) x epsilon R, x!=-2 (d) x epsilon (-oo,-1]

If f(x) ={((sqrt(1+kx)- sqrt(1-kx))/x, -1 le x le0),(2x^(2)+3x-2, 0 lex le1):} is continuous at x = 0, thenk =

The domain of the function f(x)=sqrt(x^2-[x]^2) , where [x] is the greatest integer less than or equal to x , is (a) R (b) [0,oo] (c) (-oo,0) (d) none of these

The domain of the function f(x)=sqrt(x^2-[x]^2) , where [x] is the greatest integer less than or equal to x , is (a) R (b) [0,oo] (c) (-oo,0) (d) none of these

If the function f(x)=x^(2)-kx+5 is increasing on [2,4], then (a) k in(2,oo)(b)k in(-oo,2)(c)k in(4,oo)(d)k in(-oo,4)