A pendulum of length `l=1m` is released from `theta_(0)=60^(@)` . The rate of change of speed of the bob at `theta=30^(@)` is.

A pendulum of length  = 1 m is released from 0 = 60º. The rate of change of speed of the bob at  = 30º is: (g = 10 m/s2)

A pendulum bob of mass m and length L is released from angle theta with the vertical. Find (a) the speed of the bob at the bottom of the swing and (b) tension in the string at that time

A pendulum of mass 1 kg and length  = 1m is released from rest at angle  = 60º. The power delivered by all the forces acting on the bob at angle  = 30º will be: (g = 10 m/s2)

A pendulum of mass 1 kg and length  = 1m is released from rest at angle  = 60º. The power delivered by all the forces acting on the bob at angle  = 30º will be: (g = 10 m/s2)

The figure shows a pendulum of length l suspended at a distance x vertically above a peg. (a) The pendulum bob is deflected through an angle theta and then released. Find the speed of the bob at the instant (b) The pendulum is released when theta = 90^(@) . For what x (position of peg) will the pendulum complete the circle ? (c) The pendulum is released when theta = 60^(@) . what is the velocity of the bob as it passes position E.

The pendulum bob B of mass M is released from rest when theta=0^(@) . Determine the intitial tension in the cord and also at the instant the bob reaches point D, theta=theta_(1) . Neglect the size of the bob. Give M=3kg, theta_(1)=45^(@), L=2m,g=9.81m//s^(2) .

A pendulum bob on a 2 m string is displaced 60^(@) from the vertical and then released. What is the speed of the bob as it passes through the lowest point in its path