Home
Class 12
CHEMISTRY
An aqueous glucose solution has boiling ...

An aqueous glucose solution has boiling point of `374.19K`. Another aqueous glucose solution has a freezing point of `272.22K`. Find the molality ratio of two solution. Boiling point and freezing point of `H_(2)O373.15K` and `273.15K` respectively.

Promotional Banner

Similar Questions

Explore conceptually related problems

Elevation in boiling point of an aqueous glucose solution is 0.6, K_b for water is 0.52 K molal ""^(-1). The mole fraction of glucose in the solution is:

An aqueous solution solution of a non-volatile solute boils at 373.053K. Find its freezing point. For water, K_b=0.52K kg mol^(-1), K_f = 1.86K kg mol^(-1) Boiling point =373K, freezing point of water =273K

A 5% aqueous solution of mass of cane sugar (mw=342) has freezing point 271K. calculate the freezing point of 5% glucose solution in water, if freezing point of pure water is 273.15K.

What is the boiling point of 1 molal aqueous solution of NaCl (K_b)=0.52 K molal^-1]

A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculatge the freezing point of 5% glucose in water if freezing point of pure water is 273.15K

A 5% solution (by mass) of cane suger in water has freezing point of 271K. Calculate the freezing point of 5% glucose in water if freezing point of water is 273.15 K.

The freezing point of an aqueous solutions is 272 .93 K . Calculate the molality of the solution if molal depression constant for water is 1.86 Kg mol^(-1)

An aqueous solution freezes at 272.07K, while pure water freezes at 273K. Determine the molality of the solution. (given K_f for water= 1.86K/m

the boiling point of 0.15 molar aqueous solution of an unknown solute is 373.23 K at 1 atm . The molal elevatio constant of water is ______ K kg mol ^(-1)