Al (atomic mass =27) crystallises in a cubic system with edge length (a) equal to `4Å` its density is `2.7 g//cm^(3)` The type of the unit cell is:

Al (Atomic mass =27) crystallises in a cubic system with edge length (a) equal to 4Å its density is 2.7 g cm^(-3) Calculate the number of aluminium atoms present per unit cell

Aluminium(a.w=27) crystalises in a cubic unit cell with edge length (a)=100pm, with density 'd'=180g/cm, then type of unit cell is

Aluminium metal (atomic weight = 27 g) crystallises in the cubic system with edge length 4.0 Å . The density of metal is 27.16 amu/ Å^(3) . Determine the unit cell type and calculate the radius of the Aluminium metal.

Al (at. wt 27) crystallizes in the cubic system with a cell edge of 4.05A^(@) . Its density is 2.7gcm^(-3) . Determine the unit cell type and calculate the radius of the Al atom

An element with molor mass 27 g mol^(-1) forms a cubic unit cell with edge length 4.05 xx 10^(-8) cm . If its density is 2.7 g cm^(-3) , what is the nature of the unit cell?

Al ( at . Wt . 26.98 ) crystallizes in the cubic d system with a oo 4.05 Å . Its density is 2.7 g per cm^(3) . Determine the cell type Calculate the radius of Al atom .