`HA+OH^(-) to H_(2)O+A^(-)+q_(1) kJ`
`H^(+)+OH^(-) to H_(2)O+ q_(2) kJ`
The enthalpy of dissociation of `HA` is

HA + OH rightarrow H_(2)O + A^(-+) q_(1) kJ H^(+) + OH ^(-) rightarrow H_(2)O + q_(2)kJ the enthalpy of ionisation of HA is

HA + OH rightarrow H_(2)O + A^(-+) q_(1) kJ H^(+) + OH ^(-) rightarrow H_(2)O + q_(2)kJ the enthalpy of ionisation of HA is

Given that the data for neutralization of a weak acid (HA) and strong acid with a strong base is: HA +OH^(-) rArr A^(-) + H_(2)O: DeltaH = -41.80kJ , H^(+) + OH^(-) rArr H_(2)O, Delta H= -55.90kJ The enthalpy of dissociation of weak acid would be

Given that the data for neutralization of a weak acid (HA) and strong acid with a strong base is: HA +OH^(-) rArr A^(-) + H_(2)O: DeltaH = -41.80kJ , H^(+) + OH^(-) rArr H_(2)O, Delta H= -55.90kJ The enthalpy of dissociation of weak acid would be

Given that the data for neutralization of weak acid (HA) and strong acid is : HA+OH^(-)toA^(-)+H_(2)O , DeltaH=-41.80 kJ H^(+)+OH^(-)toH_(2)O , DeltaH=+ -55.90 kJ The enthalpy of dissociation of weak acid would be

Given : H_(2)(g) + (1)/(2) O_(2)(g) = H_(2)O(g) + q_(1) H_(2)(g) + (1)/(2) O_(2)(g) = H_(2)O(l) + q_(2) The enthalpy of vaporisation of water is equal to

If CH_(3)COOH + OH^(-) rarr CH_(3)COO^(-) + H_(2)O + x kJ H^(+) + OH^(-) rarr H_(2)O + y kJ The enthalpy change for the reaction : CH_(3)COOH rarr CH_(3)COO^(-) + H^(+) is

If CH_(3)COOH+OH^(-)toCH_(3)COO^(-)+H_(2)O+q_(1)and H^(+)+OH^(-)to H_(2)O+q_(2) , then the enthalpy change for the reaction CH_(3)COOHtoCH_(3)COO^(-)+H^(+) is "equal to :

If CH_(2)COOH+OH^(-)rarrCH_(3)COO^(-)+H_(2)O+q_(1) H^(+)+OH^(-)rarrH_(2)O+q_(2) then the enthalpy change for the equal to

If CH_(2)COOH+OH^(-)rarrCH_(3)COO^(-)+H_(2)O+q_(1) H^(+)+OH^(-)rarrH_(2)O+q_(2) then the enthalpy change for the equal to