Find the height over the eart's surface at which the weight of a body becomes half of its alue t the surface.

Find the height over the earth's surface at which the weight of a body becomes half of its value t the surface.

(a) Find the acceleration due to gravity in a mine of depth 640 km if the value at the surface is 9.800 m//s^(2) . The radius of the earth is 6400 km (b) Find the height over the earth's surface at which the weight of a body becomes half of its value at the surface.

The height above the earth s surface at which the weight of a person becomes 1/4th of his weight on the surface of earth is (R is the radius of earth)

The height above the earth s surface at which the weight of a person becomes 1/4th of his weight on the surface of earth is (R is the radius of earth)

If R is the radius of earth , the height ,at which the weight of a body becomes 1/4 of its weight on the surface of earth , is

If R is radius of the earth, the height above the surface of the earth where the weight of a body is 36% less than its weight on the surface of the earth is

If R is radius of the earth , the height above the surface of the earth where the weight of a body is 36% less than its weight on the surface of the earth is