Cut off potential for a metal in photoclectric effect for light of wavelength `lambda_(1), lambda_(2)` and `lambda_(3)` is found to be `V_(1),V_(2)` and `V_(3)` volts , If `V_(1),V_(2)` and `V_(3` are in Arithmetic progression then `lambda_(1),lambda_(2)` and `lambda_(3)` will be in

Cut off potentials for a metal in photoelectric effect for light of wavelength lambda_(1), lambda_(2) and lambda_(3) is found to be V_(1), V_(2) and V_(3) volts if V_(1), V_(2) and V_(3) are in Arithmetic Progression and lambda_(1), lambda_(2) and lambda_(3) will be :

The wavelengths of violet, yellow and red light are lambda_(v), lambda_(y) and lambda_(r) respectively, then …………

The stopping potential for a certain photocell is 1.2 V when light of wavelength lambda_(1)=400 nm is used. It is 0.6 V, when light of wavelength lambda_(2)=500 nm is used. What would be the stopping potential, when both lambda_(1) and lambda_(2) are incident simultaneously ?

Transition between three energy energy levels in a particular atom give rise to three Spectral line of wevelength , in increasing magnitudes. lambda_(1), lambda_(2) and lambda_(3) . Which one of the following equations correctly ralates lambda_(1), lambda_(2) and lambda_(3) ? lambda_(1)=lambda_(2)-lambda_(3) lambda_(1)=lambda_(3)-lambda_(2) (1)/(lambda_(1))=(1)/(lambda_(2))+(1)/(lambda_(3)) (1)/(lambda_(2))=(1)/(lambda_(3))+(1)/(lambda_(1))

The wavelengths and frequencies of photons in transition 1,2 and 3 for hydrogen like atom are lambda_(1),lambda_(2),lambda_(3), v_(1),v_(2) and v_(3) respectively. Then:

The wavelengths and frequencies of photons in transition 1,2 and 3 for hydrogen like atom are lambda_(1),lambda_(2),lambda_(3), v_(1),v_(2) and v_(3) respectively. Then:

In hydrogen atom, if lambda_(1),lambda_(2),lambda_(3) are shortest wavelengths in Lyman, Balmer and Paschen series respectively, then lambda_(1):lambda_(2):lambda_(3) equals

A charged particle is accelerated from rest through a certain potenetial difference. The de-Broglie wavelength is lambda_(1) when it is acceleated through V_(1) and is lambda_(2) when accelerated through V_(2) . Then ratio lambda_(1)//lambda_(2) is

If K_(1) and K_(2) are maximum K.E. photoelectron emitted when lights wavelength lambda_(1) and lambda_(2) respectively incident a metallic surface .If lambda_(1)=3lambda_(2) ,then…..