A stretcded sting resomates with tuning fork of frequency 512 Hz. When length o fthe string is 0.5 m. the length of the string required to vibrate resonantly with a tuning fork of frequeny 256 Hz would be

A vibrating stretched string resonates with a tuning fork of frequency 512 Hz when the length of the string is 0.5 m . The length of the string required to vibrate resonantly with a tuning fork of frequency 256 Hz would be ……… .

A stretched string resonates with a tuning fork of frequency 480 Hz, when the length of the string is 60 cm. The length of the same string required to vibrate resonantly with a tuning fork of frequency 240 Hz will be

A stretched string resonates with a tuning fork of frequency 500 Hz, when the length of the string is 0.75 m. If a tuning fork of frquency 250 Hz is used, then the new resonating length will be

A stretched wire under a tension of 4 kg wt is in unison with a tuning fork of frequency 512 Hz. How should the tension be altered to make the wire vibrate in unison with a tuning fork of frequency 256 Hz ?

A stretched string is in unison with a tuning fork of frequency 392Hz. If the length of the string is decreased by 2% , then the number of beats heard per second will be

The frequency of tuning fork is 256 Hz. It will not resonate with a fork of frequency

The frequency of tuning fork is 256 Hz. It will not resonate with a fork of frequency

A stretched string is in resonance with a tuning fork of frequency 250 Hz. If the distance between two consecutive antinodes on the string is 5, then the velocity of the progressive wave in the string is

The length of pipe 4cm in diameter and open at both ends when it is set into vibrations by a tuning fork of frequency 288Hz. (v=332m/s)

A tuning fork gives 5 beats with another tuning fork of frequency 100 Hz . When the first tuning fork is loaded with wax, then the number of beats remains unchanged, then what will be the frequency of the first tuning fork