The mass defect for the nucleus of helium is `0.0303` a.m.u. What is the binding energy per nucleon for helium in `MeV` ?

The mass defect of ""_(2)^(4)He is 0.03 u. The binding energy per nucleon of helium (in MeV) is

The mass defect of He_(2)^(4) He is 0.03 u. The binding energy per nucleon of helium (in MeV) is

If the mass defect of ""_(4)^(9)X is 0.09 a.m.u. then the binding energy per nucleon is (1 a.m.u= 931.5 MeV)

If the mass defect of ""_(4)^(9)X is 0.099 a.m.u. , then binding energy per nucelon is (1 a.m.u, 931.5 MeV)

The mass of helium nucleus is less than that of its consitiuent particles by 0.03 a. m. u. The binding energy per nucleon of ._(2) He^(4) nucleus will be -

If the mass defect of ""_(4)^(9)X is a.m.u., then binding energy per nucleon is (1 a.m.u. = 931.5 MeV):