Let A, B, C be pariwise independent events with `P(C) >0 and P(AnnBnnC) = 0`. Then `P((A^c nn B^c)/C)`.

Let A,B,C be pairwise indepeendent events with P(C ) gt 0 and P(A cap B cap C ) = 0 Then P(A^(C )B^(C )//C) is :

Let E^(c) denote the complement of an event E . Let E,F,G be pairwise independent events with P(G)>0 and P(E nn F nn G)=0 Then P(E^(c)nn F^(c)nn G) equals (A)P(E^(c))+P(F^(c)) (B) P(E^(c))-P(F^(c))(C)P(E^(c))-P(F)(D)P(E)-P(F^(c))

Let E^c denote the complement of an event E. Let E,F,G be pairwise independent events with P(G) gt 0 and P(E nn F nn G)=0 Then P(E^c nn F^c nn G) equals (A) P(E^c)+P(F^c) (B) P(E^c)-P(F^c) (C) P(E^c)-P(F) (D) P(E)-P(F^c)

Let E^c denote the complement of an event E. Let E,F,G be pairwise independent events with P(G) gt 0 and P(E nn F nn G)=0 Then P(E^c nn F^c nn G) equals (A) P(E^c)+P(F^c) (B) P(E^c)-P(F^c) (C) P(E^c)-P(F) (D) P(E)-P(F^c)

Let E^c denote the complement of an event E. Let E,F,G be pairwise independent events with P(G) gt 0 and P(E nn F nn G)=0 Then P(E^c nn F^c | G) equals

Let E^c denote the complement of an event E. Let E,F,G be pairwise independent events with P(G) gt 0 and P(E nn F nn G)=0 Then P(E^c nn F^c | G) equals

If A,B,C are three pairwise independent events such that P(AnnBnnC)=0 then P((B^cnnC^c)/A) is equal to-

A and B are two independent events P(A) = 1/3 and P(A nnB) = 1/6 , then P(A^C nn B^C) will be

Let A and B be independent events such that P(A) =0.6 and P(B ) =0.4. find P(A nn B)

Suppose A and B are independent events with P (A)= 0.6 P (B) = 0.7. Compute P ( A^(c ) nn B ^(c ))