In an experiment for positive ray analysis with Thomson method, two identical parabola are obtianed when applied electric fields are `3000` and `2000 V//m`. The particles are singly ionised particles assuming same magnetic field :

When does a charged particle moving in a magnetic field experience no force? .

In the J.J. Thomson method for the determination of e//m , what is the angle between the magnetic and electric fields to which the electrons are subjected ?

If a beta particle enters in magnetic and electric field with its velocity pointing in the same direction as electric and magnetic field then :

What should be the angle between the velocity vector of the charged particle and the magnetic field to experience a maximum force, when a charged particle is moving in a uniform magnetic field?

In Thomson's method of determining e/m of cathode rays, magnetic field (B) and electric field ( E) are parallel a parabola is not. Obtained on the screen. The reason is _______ .

Revision |When the charged particle is moving at an angle to the field |Motion of a charged particle in combined electric and magnetic field

A particle having charge q moves with a velocity v through a region in which both an electric field vecE and a magnetic field B are present. The force on the particle is

A particle having charge q moves with a velocity v through a region in which both an electric field vecE and a magnetic field B are present. The force on the particle is

A uniform electric field E exists in a region of space. A charged particle is projected in the plane of electric field making an angle 0 with the direction of field. Is it possible to make the particle move in a straight line by applying a uniform magnetic field?