[" Substance "A_(2)B(9)" can undergoes decomposition to form two set of products: "],[A_(2)B(g)]

Substance A_(2)B(g) can undergoes decomposition to form two set of products : If the molar ratio of A_(2)(g) to A(g) is 5 : 3 in a set of product gases, then the energy involved in the decomposition of 1 mole of A_(2)B(g) is :

Substance A_(2)B(g) can undergoes decomposition to form two set of products : If the molar ratio of A_(2)(g) to A(g) is 5 : 3 in a set of product gases, then the energy involved in the decomposition of 1 mole of A_(2)B(g) is :

Substance A_(2)B(g) can undergoes decomposition to form two set of products : If the molar ratio of A_(2)(g) to A(g) is 5 : 3 in a set of product gases, then the energy involved in the decomposition of 1 mole of A_(2)B(g) is :

Substance A_(2)B(g) can undergoes decomposition to form two set of products : If the molar ratio of A_(2)(g) to A(g) is 5 : 3 in a set of product gases, then the energy involved in the decomposition of 1 mole of A_(2)B(g) is :

Substance A_(2)B(g) can undergoes decomposition to form two set of products : If the molar ratio of A_(2)(g) to A(g) is 5 : 3 in a set of product gases, then the energy involved in the decomposition of 1 mole of A_(2)B(g) is :

Two substance A_(2)(g) and B_(2)(g) are allowed to react to form either of A_(2)B_(2)(l), A_(2)B_(4)(g) or both depending on relative amount. Answer the following the following question, if 75 g A_(2) and 200g B_(2) are mixed and no reactant is left. [Given :At mass of A =25 , B=50] What is the volume of all the gases present in the mixture after completion of reaction at 760 mm of Hg and 273^(@) C?

Two substance A_(2)(g) and B_(2)(g) are allowed to react to form either of A_(2)B_(2)(l) , A_(2)B_(4)(g) or both depending on relative amount. Answer the following the following question, if 75 g A_(2) and 200g B_(2) are mixed and no reactant is left. [Given :At mass of A =25 , B=50] Now A_(2)B_(4) is transferred to another container completey . At high temperature it is completely dissociated in its gaseous elements A_(2) and B_(2) . Find average molecular weight of gaseous mixture:

A_(2)+2B_(2)rarrA_(2)B_(4) (3)/(2)A_(2)+2B_(2)rarrA_(3)B_(4) Two substance A_(2) & B_(2) react in the above manner when A_(2) is limited it gives A_(2)B_(4) in excess gives A_(3)B_(4^(.) A_(2)B_(4) can be converted to A_(3)B_(4) when reacted with A_(2) . Using this information calculate the composition of the final mixture when the mentioned amount of A % B are taken :c (a) 4 mole A_(2) & 4 mole B_(2) (b) (1)/(2) moles A_(2) & 2 moles B_(2) (c ) 1.25 moles A_(2) & 2 moles B_(2)