If light of wavelength `lambda_(1)` is allowed to fall on a metal , then kinetic energy of photoelectrons emitted is `E_(1)`. If wavelength of light changes to `lambda_(2)` then kinetic energy of electrons changes to `E_(2)`. Then work function of the metal is

When the incident wavelengths are lamda and lamda//2 the kinetic energies of the emitted photo electrons are E and 2E. The work function of the metal is

When the incident wavelengths are lamda and lamda//2 the kinetic energies of the emitted photo electrons are E and 2E. The work function of the metal is

Maximum kinetic energy of a photoelectron is E when the wavelength of incident light is lambda . If energy becomes four times when wavelength is reduced to one thrid, then work function of the metal is

Maximum kinetic energy of a photoelectron is E when the wavelength of incident light is lambda . If energy becomes four times when wavelength is reduced to one thrid, then work function of the metal is

Light of wavelength 500 nm falls on a metal whose work function is 1.9 eV. find the kinetic energy of the photo electrons emitted.

In a photo-emissive cell, with exciting wavelength lambda_1 , the maximum kinetic energy of electron is K. If the exciting wavelength is changed to lambda_2 , the maximum kinetic energy of electron is 2K then

In a photo-emissive cell, with exciting wavelength lambda_1 , the maximum kinetic energy of electron is K. If the exciting wavelength is changed to lambda_2 , the maximum kinetic energy of electron is 2K then

Initially a photon of wavelength lambda_(1) falls on the photocathode and emits of maximum energy E_(1) .If the wavelength of the incident photon is changed to lambda_(2) the maximum energy of the electron emitted becomes E_(2) .Then value of he (h=Planck's constant,c= velocity of light) is