int(x+1)/(x^(2)+4x-5)dx

int(2x+1)/(x^(2)+4x-5)dx

Evaluate: int(1)/(x^(2)+4x-5)dx

int(1)/(x^(2)(4x+5))dx=

int(1)/(4x^(2)-4x+5)dx

int(1)/(x^(2)+4x+5)dx

int(dx)/(x^(2)-4x+5)

int (2x+1)/(x^2+4x-5) dx

If int(x+1)/((x^(2)+4x+5)^(2))dx=f(x)+g(x)+c where f(0)= (-3)/(10) , g(-1)= (-pi)/(8) and c is any arbitrary constant, if value of f(1)+g(sqrt(3)-2)=-(1)/(5)-(pi)/(k) , then k:

int (x-2)/(x^(2)-4x+5)dx=