`Zn^(+2)` dissolves in excess of NaOH due to the formation of

If group IV the ppt of Zn(OH)_(2) dissolve in excess of NaOH due to the formation of

Solution of ZnS in dil HCl , when treated with NaOH solution , a white ppt. is formed which dissolves in excess of NaOH due to the formation of :

Zinc(II) ion on reaction with NaOH first give a white precipitate which dissolves in excess of NaOH due to the formation of :

Zinc(II) ion on reaction with NaOH first give a white precipitate which dissolves in excess of NaOH due to the formation of :

Silicon dissolves in excess of HF due to formation of

Silicon dissolves in excess of HF due to formation of

Silicon dissolves in excess of HF due to formation of

Silver chloride dissolves in excess ammonia due to the formation of a soluble compplex whose formula is