A particla starting from rest undergoes acceleration given by `a=|t-2|" m/s"^(2)` where t is time in sec. Find velocity of particle after 4 sec. is :-

A particle starts from rest at t=0 and moves along a straight line with a variable acceleration given by a (t)=(3t+1)ms^(-2) ,where t],[ is in seconds.The velocity of the particle at t=4s is

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

A particle starts from rest on a straight path, Its acceleration is linearly varying with time, such that velocity of the particle at t=2 sec and t=4 sec is 6ms^(-1) respectively. Find acceleration of the particle at t=i sec.

[" A particle starts from "],[" rest at "t=0" and moves "],[" along a straight line with "],[" a variable acceleration "],[" given by a "(t)=(3t+1)ms^(-2)],[" where "t" is in seconds."],[" The velocity of the "],[" particle at "t=4s" is "]

A particle starts from rest with a time varying acceleration a=(2t-4) . Here t is in second and a in m//s^(2) Maximum velocity of particle in negative direction is at t= …………… second

A particle starts from rest with a time varying acceleration a=(2t-4) . Here t is in second and a in m//s^(2) Maximum velocity of particle in negative direction is at t= …………… second

A particle starts from rest with a time varying acceleration a=(2t-4) . Here t is in second and a in m//s^(2) The velocity time graph of the particle is

A particle starts from rest with a time varying acceleration a=(2t-4) . Here t is in second and a in m//s^(2) The velocity time graph of the particle is