An unopened soda has an aqueous concentration of `CO_(2)`at`25^@`equal to `0.0408`molal.Thus ,pressure of `CO_(2)`gas in the can is `(K_(H)=0.034 mol//kg ba r)`

Options

A. `0.671`bar
B. `1.49`bar
C. `1.41`bar
D. `1.71` bar

Explanation

To find the pressure of CO₂ gas in the unopened soda can, we can use Henry's Law, which states that the solubility of a gas in a liquid is directly proportional to the pressure of that gas above the liquid. The relationship can be expressed as:

\[ C = K_H \cdot P \]

Where:
- \( C \) is the concentration of the gas in the solution (in mol/kg),
- \( K_H \) is Henry's constant (in mol/kg·bar),
- \( P \) is the pressure of the gas (in bar).

### Step-by-Step Solution:

1. **Identify the given values**:
- The aqueous concentration of CO₂, \( C = 0.0408 \, \text{mol/kg} \).
- Henry's constant for CO₂, \( K_H = 0.034 \, \text{mol/kg·bar} \).

2. **Rearrange Henry's Law to solve for pressure \( P \)**:
\[ P = \frac{C}{K_H} \]

3. **Substitute the known values into the equation**:
\[ P = \frac{0.0408 \, \text{mol/kg}}{0.034 \, \text{mol/kg·bar}} \]

4. **Calculate the pressure**:
\[ P = \frac{0.0408}{0.034} \approx 1.2 \, \text{bar} \]

5. **Final answer**:
The pressure of CO₂ gas in the unopened soda can is approximately \( 1.2 \, \text{bar} \).