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Mixture of volatile components A and B h...

Mixture of volatile components A and B has a total vapour pressure (in torr)p=`254-119 x_(A)`is where`x_(A)`mole fraction of A in mixture .Hence`P_(A)^@`and `P_(B)^@`are(in torr)

A

`254,119`

B

`119,254`

C

`135,254`

D

`119,373`

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To solve the problem, we need to find the vapor pressures of pure components A and B, denoted as \( P_A^0 \) and \( P_B^0 \) respectively. We are given the total vapor pressure \( P \) as a function of the mole fraction of component A, \( x_A \). ### Step-by-Step Solution: 1. **Understand the Given Equation**: The total vapor pressure \( P \) of the mixture is given by the equation: \[ P = 254 - 119 x_A \] Here, \( x_A \) is the mole fraction of component A in the mixture. 2. **Identify the Relationship**: According to Raoult's Law, the total vapor pressure of a mixture of two volatile components A and B can be expressed as: \[ P = P_A^0 x_A + P_B^0 x_B \] where \( x_B = 1 - x_A \). 3. **Substituting for \( x_B \)**: We can substitute \( x_B \) into the equation: \[ P = P_A^0 x_A + P_B^0 (1 - x_A) \] This simplifies to: \[ P = P_A^0 x_A + P_B^0 - P_B^0 x_A \] Rearranging gives: \[ P = (P_A^0 - P_B^0) x_A + P_B^0 \] 4. **Comparing Coefficients**: Now we can compare the coefficients of \( x_A \) from both expressions for \( P \): - From the given equation: The coefficient of \( x_A \) is \(-119\). - From our rearranged equation: The coefficient of \( x_A \) is \( P_A^0 - P_B^0 \). Therefore, we have: \[ P_A^0 - P_B^0 = -119 \quad \text{(1)} \] 5. **Finding the Constant Term**: The constant term from the given equation is \( 254 \), which corresponds to \( P_B^0 \) in our rearranged equation: \[ P_B^0 = 254 \quad \text{(2)} \] 6. **Substituting to Find \( P_A^0 \)**: Now we can substitute \( P_B^0 \) from equation (2) into equation (1): \[ P_A^0 - 254 = -119 \] Solving for \( P_A^0 \): \[ P_A^0 = 254 - 119 = 135 \] 7. **Final Results**: Thus, the vapor pressures of pure components A and B are: \[ P_A^0 = 135 \, \text{torr} \] \[ P_B^0 = 254 \, \text{torr} \] ### Summary of Results: - \( P_A^0 = 135 \, \text{torr} \) - \( P_B^0 = 254 \, \text{torr} \)

To solve the problem, we need to find the vapor pressures of pure components A and B, denoted as \( P_A^0 \) and \( P_B^0 \) respectively. We are given the total vapor pressure \( P \) as a function of the mole fraction of component A, \( x_A \). ### Step-by-Step Solution: 1. **Understand the Given Equation**: The total vapor pressure \( P \) of the mixture is given by the equation: \[ P = 254 - 119 x_A ...
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