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The vapour pressure of pure liquid solve...

The vapour pressure of pure liquid solvent 0.50 atm. When a non-volatile solute B is added to the solvent, its vapour pressure drops to 0.30 atm. Thus, mole fraction of the component B is

A

`0.6`

B

`0.25`

C

`0.45`

D

`0.75`

Text Solution

Verified by Experts

The correct Answer is:
A

Binary mixture contain non-volatile solute (B) in volatile solvent. By Raoult's law, relative decrease in vapour pressure =
`(DeltaP)/(P^(@))=chi_(solute)=0.6`
`rArr(0.30)/(0.50)=chi_("solute")`
`:. chi_("solute")=0.6`
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