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The vapour pressure of pure water at 75...

The vapour pressure of pure water at `75^(@)`is `296`torr the vapour pressure lowering due to `0.1`m solute is

A

`0.533`torr

B

`0.296`torr

C

`0.333` torr

D

`0.428` torr

Text Solution

Verified by Experts

The correct Answer is:
A
`(cancelOP)/(296)=(0.1)/(0.1+(1000)/(18))`
where `(1000)/(18)`=No. of moles water
`:.DeltaP=0.533` torr
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